[algospot/C] URI

URI

문제

URI (Uniform Resource Identifier) is a compact string used to identify or name resources on the Internet. Some examples of URI are below:

• http://icpc.baylor.edu.cn/
• mailto:foo@bar.org
• ftp://127.0.0.1/pub/linux
• readme.txt

When transmitting URIs through the Internet, we escape some special characters in URIs with percent-encoding. Percent-encoding encodes an ASCII character into a percent sign (“%”) followed by a two-digit Hexadecimal representation of the ASCII number. The other characters are not touched in the encoding process. The following table shows the special characters and their corresponding encodings:

Special Character	Encoded String
      " "	            %20
      "!"	            %21
      "$"	            %24
      "%"	            %25
      "("	            %28
      ")"	            %29
      "*"              	%2a

Note that the quotes are for clarity only.

Write a program which reverses this process.

입력

The first line of the input file will contain the number of test cases C (1≤C≤100). The following C lines will each contain a test case — which is the percent-encoded URI. Their length will be at most 80.

2
Happy%20Joy%20Joy%21
http://algospot.com/%2a

출력

Print one line for each test cases — the decoded original URI.

Happy Joy Joy!
http://algospot.com/*	

---

나의 풀이

#include <stdio.h>
#include <string.h>

int main()
{
	int C;
	scanf("%d", &C);

	while(C--)
	{
		char str[81];
		scanf("%s", str);
		for (int i = 0 ; i < 80 ; i++)
		{
			if (str[i] == '\0')
			{
				printf("\n");
				break;
			}
			if (str[i] == '%')
			{
				i++;
				if (str[i] == '2')
				{
					i++;
					if (str[i] == '0') printf(" ");
					else if (str[i] == '1') printf("!");
					else if (str[i] == '4') printf("$");
					else if (str[i] == '5') printf("%%");
					else if (str[i] == '8') printf("(");
					else if (str[i] == '9') printf(")");
					else if (str[i] == 'a') printf("*");
				}
			}
			else
				printf("%c", str[i]);
		}
	}
	return 0;
}

가장 빠른 풀이

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